Voltage Divider

Easy#engineering #electronics· solved by 0 · time limit 2.0 s

Two resistors in series across $V_{in}$ form a voltage divider: $V_{out} = V_{in} \cdot \frac{R_2}{R_1 + R_2}$ . Print $V_{out}$ with 2 decimals.

Input

$V_{in}$ , $R_1$ , $R_2$ on one line.

$V_{out}$

$0 < V_{in} \le 1000$ , $1 \le R_1, R_2 \le 10^7$

Input

5 10000 10000

Output

2.50

Input

12 10000 4700

Output

3.84