555 Timer Frequency

Easy#engineering #electronics· solved by 0 · time limit 2.0 s

In astable mode a 555 timer oscillates at $f = \frac{1.44}{(R_1 + 2R_2)C}$ with duty cycle $D = \frac{R_1 + R_2}{R_1 + 2R_2} \times 100\%$ . Print $f$ in Hz (2 decimals) and $D$ in percent (1 decimal).

Input

$R_1$ (Ω), $R_2$ (Ω), $C$ (µF).

Output

$f$ and $D$ .

Constraints

$1 \le R_1, R_2 \le 10^7$ , $10^{-4} \le C \le 10^4$

Sample 1

Input

1000 10000 10

Output

6.86 52.4

Sample 2

Input

10000 10000 1

Output

48.00 66.7